Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 16)
16.
If a 30 m chain diverges through a perpendicular distance d from its correct alignment, the error in length, is
.Discussion:
21 comments Page 1 of 3.
Sammy said:
7 years ago
For example, You are on the sloped surface and you are measuring horizontal distances, so here one end is fixed and when you move to the other end on a sloped surface, there will be the difference in elevations from two ends of the chain,
NOW, HERE WILL COME ERROR BECAUSE OF THE EARTHS CURVATURE, and that error is cumulative (an error will add with slope length). so the formula is h2/2l = d2/2*30 = d2/60 , (d= verticle distance)
NOW, HERE WILL COME ERROR BECAUSE OF THE EARTHS CURVATURE, and that error is cumulative (an error will add with slope length). so the formula is h2/2l = d2/2*30 = d2/60 , (d= verticle distance)
(3)
Er Meghanada (Bhadrak ) said:
8 years ago
Formula Of Alignment correction = h Square /2L,
Length of Chain (L)= 30 m.
= h Square / 2*30 m = h Square / 60 m.
(Right Answer = d square / 60 m).
Length of Chain (L)= 30 m.
= h Square / 2*30 m = h Square / 60 m.
(Right Answer = d square / 60 m).
(1)
Ashutosh said:
10 years ago
Alignment correction formula is (h^2)/2L , where h is error from correct alignment.
Atul said:
1 decade ago
As slope correction formula is h2/2d its in general chain surveying correction.
Preety said:
9 years ago
h^2/2L is the formula of alignment correction.
= h^2/2*30.
= h^2/60.
= h^2/2*30.
= h^2/60.
Anurag jain said:
7 years ago
h^2/2L is the formula of alignment correction.
= h^2/2*30.
= h^2/60.
= h^2/2*30.
= h^2/60.
(3)
Mahesh Parajuli said:
1 decade ago
h^2/(2L).
where L = Chain length.
h = Max deflection.
where L = Chain length.
h = Max deflection.
(1)
Nagaraju said:
1 decade ago
How can we determine this can you explain in detail?
PANKAJ PRAJAPATI said:
5 years ago
Alignment correction = h^2/2L = d^2/2 * 30 = d^2/60.
(10)
Goutham said:
6 years ago
Misalignment is d^2/L= d^2/30 is the right answer.
(1)
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