Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 8)
8.
The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only
Discussion:
45 comments Page 4 of 5.
Shailendra kumar mahato said:
7 years ago
For distance upto 18.2 km is 10 cm.
For distance upto 54.3 km is 30 cm.
For distance upto 91 km is 50 cm.
Ref: RS Khurmi(clause 5.1).
For distance upto 54.3 km is 30 cm.
For distance upto 91 km is 50 cm.
Ref: RS Khurmi(clause 5.1).
Ankit said:
8 years ago
I can not understand what is right and what is wrong
RAJ KUMAR said:
8 years ago
IN BC PUNMEA 12KM =1 CM.
BUT IT IS WRONG.
IN ACTUAL 18.5 KM=1CM=10MM.
This is the correct one.
BUT IT IS WRONG.
IN ACTUAL 18.5 KM=1CM=10MM.
This is the correct one.
Nayan ahir said:
8 years ago
For 18.2km - 0.1m=10cm,
For 54.3km- 0.3m=30cm,
For 91km- 0.5m=50cm.
For 54.3km- 0.3m=30cm,
For 91km- 0.5m=50cm.
Gaurav said:
8 years ago
10 mm is correct.
Angel said:
8 years ago
I think, 10mm is correct.
Avinash Gund said:
8 years ago
For 18.2 km 10 mm is correct.
For 18.5km 15 mm is correct.
For 18.5km 15 mm is correct.
Naveen said:
8 years ago
The correct answer must 15mm.
ARVIND said:
8 years ago
IT SHOULD BE 15mm.
For 12km=10mm (as per BC PUNMIA).
So,for 18.2 km = 15mm.
For 12km=10mm (as per BC PUNMIA).
So,for 18.2 km = 15mm.
Ashu said:
8 years ago
10mm = 1 cm is the correct answer.
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