Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 8)
8.
The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only
Discussion:
45 comments Page 2 of 5.
ARVIND said:
8 years ago
IT SHOULD BE 15mm.
For 12km=10mm (as per BC PUNMIA).
So,for 18.2 km = 15mm.
For 12km=10mm (as per BC PUNMIA).
So,for 18.2 km = 15mm.
Abinash said:
2 years ago
For 12km difference is 10mm.
For 18km difference will be nearly 15mm.
For 18km difference will be nearly 15mm.
(3)
Nayan ahir said:
8 years ago
For 18.2km - 0.1m=10cm,
For 54.3km- 0.3m=30cm,
For 91km- 0.5m=50cm.
For 54.3km- 0.3m=30cm,
For 91km- 0.5m=50cm.
Santosh Neelannavar said:
6 years ago
The correct answer 10cm.
18.2km =0.1m.
54.3km = 0.3m.
90km = 0.5m.
18.2km =0.1m.
54.3km = 0.3m.
90km = 0.5m.
(1)
Avinash Gund said:
8 years ago
For 18.2 km 10 mm is correct.
For 18.5km 15 mm is correct.
For 18.5km 15 mm is correct.
Anil said:
7 years ago
0.1m * 100mm.
100mm * 10cm.
So, 10 cm answer is correct.
100mm * 10cm.
So, 10 cm answer is correct.
Rakesh Kumar Chhalotre said:
7 years ago
12km - 1cm.
So, for 18.2km - 1.5cm = 15mm is correct.
So, for 18.2km - 1.5cm = 15mm is correct.
(1)
Ankit said:
8 years ago
I can not understand what is right and what is wrong
Engr said:
8 years ago
I think units are in mm not cm.
It's 10mm not 10cm.
It's 10mm not 10cm.
Jaz said:
7 years ago
15 cm .......... 18.2 km.
1 cm ............. 12 km.
1 cm ............. 12 km.
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