Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 5 (Q.No. 19)
19.
If S is the shear force at a section of an I-joist, having web depth d and moment of inertia I about its neutral axis, the difference between the maximum and mean shear stresses in the web is,
Discussion:
12 comments Page 1 of 2.
MJM Gcek said:
4 years ago
Yes, @Sree.
I agree with you. That is for rectangular only. We should subtract the two side portions from the web area to get MOI for I-joist.
I agree with you. That is for rectangular only. We should subtract the two side portions from the web area to get MOI for I-joist.
Aru said:
9 years ago
Stress = f/area.
bd^3/12= I,
Thus bd =12I/d^2,
avg stress = Sd^2/12I.
We know max stress is 1.5 * avg stress,
Diff = Sd^2/24I.
bd^3/12= I,
Thus bd =12I/d^2,
avg stress = Sd^2/12I.
We know max stress is 1.5 * avg stress,
Diff = Sd^2/24I.
Sree said:
5 years ago
Isn't it an I section, how can we take bd^3/12 as I value?
Abbas Ali said:
6 years ago
Diff is:
1.5SD^2/12I - SD^2/12I = sd^2/24I.
1.5SD^2/12I - SD^2/12I = sd^2/24I.
Indra said:
7 years ago
@Aru.
Please explain about difference.
Please explain about difference.
Dheeraj said:
6 years ago
Very very thank you @Aru.
Alana said:
9 years ago
Can anyone explain it?
Amar said:
7 years ago
My answer is S D^2/8I.
Deep Das said:
3 years ago
Well said @Abbas Ali.
(1)
Anshu pal said:
6 years ago
Option C is correct.
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