Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 25)
25.
A rectangular beam 20 cm wide is subjected to a maximum shearing force of 10, 000 kg, the corresponding maximum shearing stress being 30 kg/cm2. The depth of the beam is
Discussion:
26 comments Page 1 of 3.
Bibek dey said:
9 years ago
Since, maximum shearing stress = 1.5 * average shearing stress.
Average shearing stress = V/bd (V=shear force). 30 = 1.5 * 10000(20/d).
So, d = 25 cm.
Average shearing stress = V/bd (V=shear force). 30 = 1.5 * 10000(20/d).
So, d = 25 cm.
(5)
Arpita saxena said:
1 decade ago
Max. shear stress = 1.5*avg.shear stress.
Avg.shear stress = S.F/(B*d).
Avg.shear stress = 10000/(20*d).
30 = 1.5*10000/(20*d).
d = 25cm.
Avg.shear stress = S.F/(B*d).
Avg.shear stress = 10000/(20*d).
30 = 1.5*10000/(20*d).
d = 25cm.
(3)
Ajay Reddy said:
1 year ago
Let's
Maximum shear stress in rectangular beam = 3 ÷ 2 avg shear stress
30 = 3 ÷ 2(10000÷20×d)
30 = 750 ÷ d.
d = 750 ÷ 30.
D = 25cm.
Maximum shear stress in rectangular beam = 3 ÷ 2 avg shear stress
30 = 3 ÷ 2(10000÷20×d)
30 = 750 ÷ d.
d = 750 ÷ 30.
D = 25cm.
(5)
Mounika Reddy said:
1 decade ago
T = SQ/Ib.
S=10000, T=30, Q=bh^2/8, I=bh^3/12.
Then h = 25cm,
or
Tmax = (3*Vmax)/(2*A).
h = 25cm, how will be 15cm.
S=10000, T=30, Q=bh^2/8, I=bh^3/12.
Then h = 25cm,
or
Tmax = (3*Vmax)/(2*A).
h = 25cm, how will be 15cm.
Abhay said:
10 years ago
Maximum shearing stress σ max = 3P/2(bd).
where P = Shearing force.
30 = 3*10000/(2*20*d) => d = 25 cm.
where P = Shearing force.
30 = 3*10000/(2*20*d) => d = 25 cm.
Aravind said:
3 years ago
But how will max shear force create average shear stress instead of max shear stress? Please explain me.
(4)
Krishna said:
9 years ago
Convert the given max to average shear stress and then proceed using,
T(max) = 2/3 ( T(avg)).
T(max) = 2/3 ( T(avg)).
Katakam saketh said:
8 years ago
Here, qmax=(1.5)*(F/bd).
F = 10000,b=20,qmax=30,d=?.
30 = 1.5*10000/(20*d),
d = 25cm.
F = 10000,b=20,qmax=30,d=?.
30 = 1.5*10000/(20*d),
d = 25cm.
(1)
Vijay kumar s said:
5 years ago
According to me, max shear stress = 3P/2BD.
(1)
Dipak M said:
5 years ago
Thanks all for explaining the answer.
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