Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 5 (Q.No. 26)
26.
The cross sections of the beams of equal length are a circle and a square whose permissible bending stress are same under same maximum bending. The ratio of their flexural weights is,
Discussion:
13 comments Page 2 of 2.
Devendra singh said:
6 years ago
Stress the same relationship sectional modulus ratio.
Circle sectional modulus= &pi& * d^3/16.sovle .19625.
Square z = d^3/6. Solve 1/6=.1667.
Ratio = .19625/.1667 = 1.118.
Circle sectional modulus= &pi& * d^3/16.sovle .19625.
Square z = d^3/6. Solve 1/6=.1667.
Ratio = .19625/.1667 = 1.118.
Sunn said:
6 years ago
Could not understand it. Please explain in detail.
Raj said:
4 years ago
@Devendra Singh
The SECTION MODULUS FOR CIRCLE IS (π*d^3/32) polar sec mod is (π*d^3/16) so the correct answer is 0.589.
The SECTION MODULUS FOR CIRCLE IS (π*d^3/32) polar sec mod is (π*d^3/16) so the correct answer is 0.589.
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