Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 22)
22.
An open-ended cylinder of radius r and thickness t is subjected to internal pressure p. The Young's modulus for the material is E and Poisson's ratio is μ. The longitudinal strain is
zero
none of these.
Discussion:
18 comments Page 1 of 2.
Utsav Manandhar said:
9 years ago
I think it is option B.
Affricate said:
9 years ago
Anyone explain.
Apcivilian said:
9 years ago
I think, It should be C.
Umesh said:
9 years ago
The answer should be D.
Yogesh said:
9 years ago
Due to Internal pressure, only radial strain is caused, So longitudinal strain should be ZERO.
Akib said:
9 years ago
In open end no pressure is required so pressure is zero longitudinal strain is zero.
Kiran said:
8 years ago
Correct @Yogesh.
Abhi said:
8 years ago
Longitudinal stress= PD/4t.
E=stress/strain.
D=2r.
Substitute. You'll get the answer as option C.
E=stress/strain.
D=2r.
Substitute. You'll get the answer as option C.
Shashi Ranjan said:
8 years ago
C would be the correct answer.
Ram Prasad Poudel said:
8 years ago
The answer given above is right i.e zero because it is the case of open-ended cylinder where no longitudinal stress is developed hence no longitudinal strain.
@Abhi.
This case is for a cylinder with closed ends.
@Abhi.
This case is for a cylinder with closed ends.
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