Discussion :: Strength of Materials - Section 1 (Q.No.33)
|Kashi said: (Sep 24, 2013)|
|Maximum bending moment occurs at zero shear force*.
d(M)/dx = 0 (for maximum bending moment).
on differentiating above equation you get option C.
|Maneesha said: (Aug 15, 2017)|
|Give me the correct explanation.|
|Ebeyehu said: (Aug 21, 2017)|
|The derivation of the moment is always shear having this idea we can derivate and we obtain dm/dx =a (1-3x*x/l*l) say this equation is zero and we will get 1-3x*x/l*l =0 from this x=l/3thepower of half.|
|Venkatesh said: (Oct 17, 2017)|
|Shear force is the partial derivative of bending moment so to obtain shear force the given bending moment is differentiated with respect to x and submit the given options so that you should get zero.|
|Hussein said: (May 27, 2019)|
|1-(3x2/l2) = 00.
|Anjali said: (Dec 24, 2019)|
|Shear force always zero at maximum bending moment.
For max BM,dm/dx =0.
So 1-3x^2/l^2 =0.
|Shreyas A said: (Oct 31, 2020)|
|We know that,
Rate of change of Bending moment, dM/dx = Shear force.
Rate of change of Shear force, dF/dx = Rate of loading.
So, they gave B.moment as an equation. To get Shear force then differentiate that wrt x and we will get,
dM/dx = a( 1 - 3x^2/l^2).
Now to get max shear force, dM/dx = 0.
so, a( 1 - 3x^2/l^2) = 0.
l^2 = 3x^2.
x = l/√2.
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