Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 5 (Q.No. 6)
6.
The B.M. diagram of the beam shown in below figure, is
Discussion:
21 comments Page 2 of 3.
Roop Kumar said:
7 years ago
Correct answer is triangular.
Mona said:
7 years ago
No load so how sfd can rectangular?
Nepali said:
7 years ago
For the moment at A: BMD is a rectangle.
For the reaction at A: BMD is a triangle.
Hence net BMD is trapezium, so the option C is correct.
For the reaction at A: BMD is a triangle.
Hence net BMD is trapezium, so the option C is correct.
Pankaj said:
7 years ago
SFD will be rectangular and BMD will be triangular.
Joydeep said:
7 years ago
@All.
SF diagram will be a straight line, here no load is applied & BM diagram will be a triangle.
SF diagram will be a straight line, here no load is applied & BM diagram will be a triangle.
Veena B.C said:
6 years ago
Yes, triangular is correct.
Sanat kumar said:
4 years ago
At A, moment is M.
At B, moment is 0.
It should be drawn to a Triangle.
At B, moment is 0.
It should be drawn to a Triangle.
MJM Gcek said:
4 years ago
It should be triangle.
Joseph Aspidin said:
4 years ago
Anyone who says BM at A is equal to M is out of their Mind.
At SS, BM =0 always because it just can't resist the applied moment. BM will be zero at both A and B.
However, BMD will be triangular. Consider it as a case of SS beam with the applied moment at the middle. This is one and the same thing.
At SS, BM =0 always because it just can't resist the applied moment. BM will be zero at both A and B.
However, BMD will be triangular. Consider it as a case of SS beam with the applied moment at the middle. This is one and the same thing.
Akash said:
3 years ago
It's triangle.
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