Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 2 (Q.No. 15)
15.
The reaction at support A of the beam shown in below figure, is
zero
5 T
10 T
1 T
4 T.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
61 comments Page 2 of 7.

Mani said:   8 years ago
In simply support beam Ra=Rb when centering load so we first change the uniform load.

To point load so,
Ra=Rb.
1*10*1/2=5T.
So reaction at Ra+Rb=5.
Ra+Ra=5 (Ra=Rb).
2ra=5.
Ra=2.5 t.

Rahul said:   9 years ago
There is Ra, Rb, Rc total load is 1 Ton and distributed in three part (wl/2).

Ra = 2.5 T
Rb = 5 T
Rc = 2.5 T
But in answers it is is not given.

Mounika reddy said:   1 decade ago
Ray+Rby = 10T.

The distri load convert to pt load 1*5 for 1st member and 1*5 for 2nd.

Take moment about A is zero Rby = 10T.

SO Ray = 0.
(1)

Roshan said:   7 years ago
If you consider a, b, c as supports from left to right, a will carry 2.5 t, b will carry 5.0t and c will carry 2.5t. Total load is 10 t.

Ashar wazir said:   8 years ago
Ra + Rb = 10t
Ra = 10t - Rb,

Therefore to find Ra take moments about A.
Rb = 10t-10t = 0.
Therefore, option A is correct.

Anubala said:   5 years ago
Ra+Rb= wl/2 = (1*10)/2= 5T---> (1).

Moment about A,
Rb*10-(1*10*10)/2=0,
Rb=5T.

Substitute in (1)
Ra=0
The answer is correct.
(2)

Shankar said:   7 years ago
The answer is not zero because under loading conditions never support reaction zero. If it's zero structure will be failure.

Yusoof said:   7 years ago
From the theorem of 3 moments (Clapyeron's method).

The support moment at the last simple support will be zero.

Krishna said:   9 years ago
Yeah! It's 3/16 wl at A and C and 5/8wl at B.

The correct answer of this problem is not given in the option.

Sajitha B said:   8 years ago
The total load is 10t. For the three supports, the reaction due to the load will be same and equal to 3.33T.


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