Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 15)
15.
The reaction at support A of the beam shown in below figure, is
Discussion:
61 comments Page 2 of 7.
Vinayak Powar said:
8 years ago
The Answer should be 2.5T.
Yusoof said:
7 years ago
From the theorem of 3 moments (Clapyeron's method).
The support moment at the last simple support will be zero.
The support moment at the last simple support will be zero.
Tayu said:
8 years ago
Assuming Ra, Rb And Rb from right to left respectively,
The beam is hyperstatic and the normal equations of static alone does not suffice, using other methods the reactions will be 3T/16, 5T/16 and 3T/16 respectively, so the right answer is not given.
The beam is hyperstatic and the normal equations of static alone does not suffice, using other methods the reactions will be 3T/16, 5T/16 and 3T/16 respectively, so the right answer is not given.
Tayu said:
8 years ago
You are right, Thanks @Gani.
Bambhaniya Sunil said:
7 years ago
5T is the correct answer.
Ammu said:
7 years ago
They asking load only not moment. Moment at the support A will be zero, Not reaction.
Ammu said:
7 years ago
They asking load only not moment. Moment at the support A will be zero, Not reaction.
Hemant chauhan said:
7 years ago
This beam is simitricaly,
Hence ra +rb = total load ÷ 2
=> 1*10 = 10 ÷ 2 =5.
Hence ra +rb = total load ÷ 2
=> 1*10 = 10 ÷ 2 =5.
KASSAHUN MRTU said:
7 years ago
2.5T is the correct answer.
Roshan said:
7 years ago
It is 2.5 t for A, 2.5t for B, and 5.0t will be support C. If you consider B as centre support.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers