Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 15)
15.
The reaction at support A of the beam shown in below figure, is
Discussion:
61 comments Page 2 of 7.
Sush said:
7 years ago
1.85 is the correct answer.
Ra=Rb=3wl/16.
Ra=Rb=3wl/16.
(1)
Harsha said:
7 years ago
It is 3/16 wl only.
Shankar said:
7 years ago
The answer is not zero because under loading conditions never support reaction zero. If it's zero structure will be failure.
AJAY said:
7 years ago
The correct answer is 5t, since SSB is symmetrical and total load is 1 * 10 = 10t, Ra=Rb=10/2= 5t.
Yusoof said:
7 years ago
From the theorem of 3 moments (Clapyeron's method).
The support moment at the last simple support will be zero.
The support moment at the last simple support will be zero.
Roshan said:
7 years ago
If you consider a, b, c as supports from left to right, a will carry 2.5 t, b will carry 5.0t and c will carry 2.5t. Total load is 10 t.
Roshan said:
7 years ago
It is 2.5 t for A, 2.5t for B, and 5.0t will be support C. If you consider B as centre support.
KASSAHUN MRTU said:
7 years ago
2.5T is the correct answer.
Hemant chauhan said:
7 years ago
This beam is simitricaly,
Hence ra +rb = total load ÷ 2
=> 1*10 = 10 ÷ 2 =5.
Hence ra +rb = total load ÷ 2
=> 1*10 = 10 ÷ 2 =5.
Ammu said:
7 years ago
They asking load only not moment. Moment at the support A will be zero, Not reaction.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers