Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 47)
47.
The ratio of the flexural strengths of two square beams one placed with its two sides horizontal and the other placed with one diagonal vertical, diagonal, is
Discussion:
6 comments Page 1 of 1.
Pramit samanta said:
4 years ago
@Krupal.
So the I is same for both case?
So the I is same for both case?
Krupal said:
6 years ago
Flexural strength is taken equal section modulus Z.
Z = I/Y.
I is same for both cases.
Z proportional to 1/Y. take square side=a.
Y1 = a/2, Y2 = a/√2.
Z1/z2 = (a/√2)/(a/2).
= √2.
Z = I/Y.
I is same for both cases.
Z proportional to 1/Y. take square side=a.
Y1 = a/2, Y2 = a/√2.
Z1/z2 = (a/√2)/(a/2).
= √2.
(1)
Sajid said:
6 years ago
Z should be the same, so 2 √2 is the answer.
Anurag said:
6 years ago
How to solve this? Please tell me.
Chulbul said:
7 years ago
M.I/y
Where M is constant for both.
I/y = z.
The ans should be 1/(√2) I guess.
Where M is constant for both.
I/y = z.
The ans should be 1/(√2) I guess.
(1)
Reshu agrawal said:
9 years ago
How to solve this question? Please tell me.
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