Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 39)
39.
The width b and depth d of a beam cut from a wooden cylindrical log of 100 cm diameter for maximum strength are :
Discussion:
8 comments Page 1 of 1.
Pratik said:
6 years ago
d= √2/3 * D, b = D/√3.
(1)
Anand said:
7 years ago
Dia of cylinder = D.
The Width of beam = b.
The Depth of beam = d.
So, D2 = b2 + d2 --> 1.
Section modulus Z = bd2/6.
Z change with breath section.
Partial derivative of b get D2 = 3b2.
Apply eqn 1.
d/b = 2^0.5.
The Width of beam = b.
The Depth of beam = d.
So, D2 = b2 + d2 --> 1.
Section modulus Z = bd2/6.
Z change with breath section.
Partial derivative of b get D2 = 3b2.
Apply eqn 1.
d/b = 2^0.5.
Manish said:
8 years ago
Explain is please.
Priya said:
8 years ago
Please explain the answer in detail.
Roy said:
8 years ago
For max strength B=D/√3 and d=D√{2/3).
(1)
Suneet said:
8 years ago
You can also compare the value of section modulus.
Kruti said:
9 years ago
How? Explain @John.
JOHN said:
10 years ago
b = D/1.732.
d = D*1.414/1.732.
d = D*1.414/1.732.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers