Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 30)
30.
In a simply supported beam (l + 2a) with equal overhangs (a) and carrying a uniformly distributed load over its entire length, B.M. at the middle point of the beam will be zero if
Discussion:
6 comments Page 1 of 1.
Manish Dhiman said:
5 years ago
For 0 , L=2a.
For BM sign changes, L>2a.
For BM sign changes, L>2a.
(1)
Roy said:
8 years ago
Ra=RB=0.5w(l+2a). So moment about mid point, 0.5w(l+2a)*l/2 - {w(a+l/2)^2}/2=0 .
Now calculate it, l= 2a.
Now calculate it, l= 2a.
Sachin Dyavappanavar said:
9 years ago
At the support, max BM is wk^2/32 and at the midpoint, BM is zero.
Aching tango said:
9 years ago
Please explain it.
How would be the figure of BMD?
How would be the figure of BMD?
Jai said:
9 years ago
Can Anyone explain me?
Jai said:
9 years ago
Anyone can explain it?
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