Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 31)
31.
If a shaft is rotating N revolutions per minute with an applied torque T kg-m, the horse power being transmitted by the shaft, is
none of these.
Discussion:
11 comments Page 1 of 2.
Joti said:
1 year ago
Thanks @Prem Prakash.
Prem prakash said:
2 years ago
T is given kg/m.
we know 1 kg = 9.81 N.
1 HP = 745 watt.
Thus.
if Torque unit in kg/m.
Then power in unit kg-m/s.
So,
T = 2πNT/60 in kg.m/s.
T= 2πNT*9.81/60 in N.m/s (watt).
T = 2πNT*9.8/60*745 in HP.
we know 1 kg = 9.81 N.
1 HP = 745 watt.
Thus.
if Torque unit in kg/m.
Then power in unit kg-m/s.
So,
T = 2πNT/60 in kg.m/s.
T= 2πNT*9.81/60 in N.m/s (watt).
T = 2πNT*9.8/60*745 in HP.
Tanmoy Karmakar said:
3 years ago
Thanks @SH civil.
Sushil said:
4 years ago
Thanks for the answer.
Mck said:
5 years ago
Agree @Sh Civil.
Sh civil said:
5 years ago
power in watts = 2πNT / 60
as torque in kg /m, T * 9.81 N.m and power is to explain in HP, 1 HP = 745.7 watts.
P in HP = 2πNT* 9.81 / 60 * 745.7.
~2πNT / 4500.
as torque in kg /m, T * 9.81 N.m and power is to explain in HP, 1 HP = 745.7 watts.
P in HP = 2πNT* 9.81 / 60 * 745.7.
~2πNT / 4500.
Rakhi said:
5 years ago
Anybody, please explain clearly, I didn't understand.
Shubham said:
5 years ago
60*745=45000 in division.
Nani said:
6 years ago
Power transmitted by shaft is = 2 * (φ) * N * T/60 watts.
In watts = Power/745.7.
In watts = Power/745.7.
Lara said:
6 years ago
Can anyone explain it?
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