Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 3 (Q.No. 15)
15.
Strain energy of a member may be equated to
average resistance x displacement
stress x strain x area of its cross-section
stress x strain x volume of the member
(stress)2 x volume of the member + Young's modulus E.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
20 comments Page 1 of 2.

Lalit said:   7 years ago
Option c is correct, if answer is option D then instead of +E, there should be /E, then both option C & D become same value.

You are absolutely right @Kajal Tomar.

Samm said:   9 years ago
@Deepak.

Option C is applicable for gradually applied load. Whereas option D is valid for both gradually & suddenly applied load.

Yogesh said:   9 years ago
Strain Energy = 1/2 Pδ.

Taking δ = PL/AE.

SE = P^2L/2AE = σ ^2V/2E.
(where σ = P/A).

Himzz said:   9 years ago
I think in the answer instead of + sign they should correct it by / (divide) sign.

Neel said:   8 years ago
Option C is correct.

And in option D there should be 1/E and in multiplication.

Deepak said:   7 years ago
Both C and D is the correct answer. Because strain is also known as stress/E.

Kajal Tomar said:   7 years ago
Option C is correct or otherwise option D but + should be ÷.
(2)

Sunil Kukadiya said:   9 years ago
0.5 * ((stress)2 x volume of the member)/(Young's modulus E).

Ritesh said:   6 years ago
1/2*stress*strain*volume (stress2/2E*volume) are same.
(1)

Bhanwar singh said:   8 years ago
C is the correct option.

D will be if /E is there.
(1)


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