Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 44)
44.
If a solid shaft is subjected to a torque T at its end such that maximum shear stress does not exceed fz the diameter of the shaft will be
none of these.
Discussion:
3 comments Page 1 of 1.
Sheela KR said:
7 years ago
Question is about to find the diameter of shaft:
i.e fs=16T/πd3.
i.e d=cube root of ( 16T/πfs).
@Priya
So, option C is correct.
i.e fs=16T/πd3.
i.e d=cube root of ( 16T/πfs).
@Priya
So, option C is correct.
(1)
Inayat Ullah Kakar said:
9 months ago
T = π × fs × d^3/16.
By Rearranging we will get the given answer.
By Rearranging we will get the given answer.
Priya said:
8 years ago
I think it's d.
Because of Max shear stress about 16T/πd3.
Because of Max shear stress about 16T/πd3.
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