Civil Engineering - Strength of Materials - Discussion

1. 

The ratio of the moments of resistance of a solid circular shaft of diameter D and a hollow shaft (external diameter D and internal diameter d), is

[A].
[B].
[C].
[D].
[E]. none of these.

Answer: Option A

Explanation:

No answer description available for this question.

Taba Amith said: (Jan 27, 2017)  
The correct answer should be C.

Ranjitha said: (Mar 29, 2017)  
I(solid shaft)= π D^4/64.
I(hollow shaft)= π (D^4-d^4)/64.
So, D^4/(D^4-d^4) is the answer.

Option A is correct.

Priya said: (Nov 18, 2017)  
Yes, A right. I agree.

Naveen Kashyap said: (Jan 15, 2018)  
The answer should be C.

Deepak said: (Jun 7, 2018)  
For solid shaft:
Tmax = (π/ 16) τmax D3.

For a hollow shaft:
Tmax = (π/ 16) τmax (D4 - d4)/D.

Utsav said: (Nov 5, 2018)  
It's solid to hollow.

A is correct.

Amu Bokato said: (Mar 8, 2019)  
Thanks all for explaining the answer.

Nabajit Sarkar said: (Mar 29, 2020)  
Deflection for UDL = (w/L)*(L^4/8EI).
=wL^3/8EI.
Deflection of Pt. Load= wL^3/3EI.
Max. Deflection = -(5/24)*(wL^3/EI).

R.K said: (Dec 4, 2020)  
M= σ *Z = π *d^3* σ /32 (for circular).

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