Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 13)
13.
If two forces acting at a joint are not along the straight line, then for the equilibrium of the joint
Discussion:
19 comments Page 1 of 2.
Inayat Ullah Kakar said:
9 months ago
The given answer is correct:
Note:
If two forces are in a straight line then option D is correct for the equilibrium condition.
Here;
the forces are not in a straight line so each force must be zero for equilibrium conditions.
Note:
If two forces are in a straight line then option D is correct for the equilibrium condition.
Here;
the forces are not in a straight line so each force must be zero for equilibrium conditions.
(5)
Sivanarayana said:
1 year ago
If two forces F1, F2 are concurrent at a joint in different directions.
Then each force had two components i.e. Horizantal and vertical components. If the joint is in equilibrium then the horizantal and vertical components of the forces must be the same magnitude in opposite directions. Then the answer is "D".
Then each force had two components i.e. Horizantal and vertical components. If the joint is in equilibrium then the horizantal and vertical components of the forces must be the same magnitude in opposite directions. Then the answer is "D".
Heer said:
6 years ago
If two forces were on a straight line then only option D would be correct.
Bt it's clearly written in the question that forces are not along the straight line so the given answer is correct.
Bt it's clearly written in the question that forces are not along the straight line so the given answer is correct.
(1)
Gopinath said:
7 years ago
If the forces not in a straight line then couple may produce so forces must be zero.
(3)
Mohan said:
8 years ago
We can't equalize the forces until they are acting in a straight line. (ie by putting equal magnitude in opposite direction). Hence the forces must be 0.
Santanu Acharya said:
8 years ago
It's based on the method of joints principle.
So, option B is correct.
So, option B is correct.
Khankir chele said:
8 years ago
Since there are two conditions:
I) Not along the st. Line.
II) It must be in equilibrium.
Hence to satisfy these two conditions there will be no magnitude of these force. Answer B is correct.
I) Not along the st. Line.
II) It must be in equilibrium.
Hence to satisfy these two conditions there will be no magnitude of these force. Answer B is correct.
Muniraj meena jodli said:
8 years ago
No option D can not be correct because it is written that they should not be in straight line please refer to question language first answer is correct B.
Asnake kebede said:
8 years ago
Option B is correct, because at a joint when two force acts as other option the joint doesn't at equilibrium.
Snehasish said:
9 years ago
Since there are two conditions:
i) Not along the st.line.
ii) It must be in equilibrium.
Hence to satisfy these two conditions there will be no magnitude of these force. Answer B is correct.
i) Not along the st.line.
ii) It must be in equilibrium.
Hence to satisfy these two conditions there will be no magnitude of these force. Answer B is correct.
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