Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 5)
5.
The section modulus of a rectangular light beam 25 metres long is 12.500 cm3. The beam is simply supported at its ends and carries a longitudinal axial tensile load of 10 tonnes in addition to a point load of 4 tonnes at the centre. The maximum stress in the bottom most fibre at the mid span section, is
Discussion:
16 comments Page 2 of 2.
Paul said:
8 years ago
How to find out A? Please explain in detail.
Muthu said:
6 years ago
Please explain the answer.
Pranjul said:
6 years ago
Area calculate from bending equation M = f * Z and f = force/area.
Shraddha said:
5 years ago
@Vipin Sainath.
Why Σ = (M/Z)*(P/A)?
Why Σ = (M/Z)*(P/A)?
Chris said:
4 years ago
@Shraddha @Kajal.
P/A represents stress.
The bending formula:
M/I = f/y.
Stress f = P/A.
Section Modulus Z = I/y.
P/A represents stress.
The bending formula:
M/I = f/y.
Stress f = P/A.
Section Modulus Z = I/y.
Supriya said:
3 years ago
Why using m/z+p/a?
It is like bending stress=M/Z know from the flexural formula. Am I right?
It is like bending stress=M/Z know from the flexural formula. Am I right?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers