Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 5)
5.
The section modulus of a rectangular light beam 25 metres long is 12.500 cm3. The beam is simply supported at its ends and carries a longitudinal axial tensile load of 10 tonnes in addition to a point load of 4 tonnes at the centre. The maximum stress in the bottom most fibre at the mid span section, is
Discussion:
16 comments Page 1 of 2.
Aspire said:
9 years ago
How to solve this?
Ramachandraraju said:
9 years ago
Anybody give explanation about this.
Akscivilian said:
9 years ago
Question is wrong ,there is needed cross-sectional area, not given so we can't find the answer.
B.S = M/Z + P/A.
M = WL/4.
But A is not given.
B.S = M/Z + P/A.
M = WL/4.
But A is not given.
Deb said:
8 years ago
Please, someone solve it clearly.
Thakur said:
8 years ago
Please explain the details.
Paul said:
8 years ago
How to find out A? Please explain in detail.
Muthu said:
6 years ago
Please explain the answer.
Pranjul said:
6 years ago
Area calculate from bending equation M = f * Z and f = force/area.
Basanth Babu said:
6 years ago
The cross sectional area of the beam is needed to solve this problem.
(2)
Vipin sainath said:
5 years ago
Bending Stress (Sigma) = M/Z x P/A.
First, we have to calculate Depth and Breadth ..From span/depth ratio we get Depth
Span/20 = 25m/20 = 1.25m or 125cm so D= 125cm, Then B/D=0.5 to 0.67 from this ratio we get breadth B,
B = Dx0.5 = 125X0.5 = 62.5 say B= 60cm, So we got B and D.
M/Z = (4000x2500/4) / 12.6 = 2,00,000 kg/cm2.
P/A = 10000/7500 =1.33 kg/cm2.
Therefore, Sigma = 200000 kg/cm2 x 1.33 kg/cm2 = 266000 Kg/cm2 or 26.6 Kg/m2
finally we got Max stress = 26.6kg/m2.
First, we have to calculate Depth and Breadth ..From span/depth ratio we get Depth
Span/20 = 25m/20 = 1.25m or 125cm so D= 125cm, Then B/D=0.5 to 0.67 from this ratio we get breadth B,
B = Dx0.5 = 125X0.5 = 62.5 say B= 60cm, So we got B and D.
M/Z = (4000x2500/4) / 12.6 = 2,00,000 kg/cm2.
P/A = 10000/7500 =1.33 kg/cm2.
Therefore, Sigma = 200000 kg/cm2 x 1.33 kg/cm2 = 266000 Kg/cm2 or 26.6 Kg/m2
finally we got Max stress = 26.6kg/m2.
(3)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers