Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 5 (Q.No. 10)
10.
The slenderness ratio of a vertical column of square cross- section of 10 cm side and 500 cm long, is
Discussion:
8 comments Page 1 of 1.
Poj said:
5 years ago
@Vaibhav
(SQRT) The square root of 833.33/10 = 2.8867.
(SQRT) The square root of 833.33/10 = 2.8867.
Vaibhav said:
7 years ago
@Shambu.
How you got 833.33/100 = 2.88?
How you got 833.33/100 = 2.88?
Shambhuu said:
7 years ago
@Chauhan.
√(833.33/100) = 2.88.
√(833.33/100) = 2.88.
Chauhan hardik said:
8 years ago
The Radius of gyration = SQRT (833.33/10) = 2.8867 cm.
how? because. 833.33/10 = 83.33.
how? because. 833.33/10 = 83.33.
AMAL ZAD said:
8 years ago
Good, Thanks @Suhasini.
Shiva said:
8 years ago
Nice explanation @Suhasini.
(1)
Naveed Kamal said:
8 years ago
S.r = L/r.
r = sqrt I/A ;( a x a3)/12 = a4/12 = ans ;a x a = ans ;a= 10 cm.
r = ans ' L =500 cm.
By applying this, you will get the answer.
r = sqrt I/A ;( a x a3)/12 = a4/12 = ans ;a x a = ans ;a= 10 cm.
r = ans ' L =500 cm.
By applying this, you will get the answer.
(1)
Suhasini said:
1 decade ago
Slenderness ratio = Length/Radius of gyration.
Radius of gyration = SQRT (I/A).
Moment of inertia (square) , I = b^4/12 = 10^4/12 = 833.33 cm4.
Area of square column = 10*10 = 100 cm2.
Radius of gyration = SQRT (833.33/10) = 2.8867 cm.
Therefore Slenderness ratio, L/Radius of gyration = 500/2.8867 = 173.2.
Radius of gyration = SQRT (I/A).
Moment of inertia (square) , I = b^4/12 = 10^4/12 = 833.33 cm4.
Area of square column = 10*10 = 100 cm2.
Radius of gyration = SQRT (833.33/10) = 2.8867 cm.
Therefore Slenderness ratio, L/Radius of gyration = 500/2.8867 = 173.2.
(5)
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