Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 23)
23.
The slenderness ratio of a vertical column of a square cross-section of 2.5 cm sides and 300 cm length, is
Discussion:
33 comments Page 2 of 4.
Ferdieb said:
9 years ago
Slenderness ratio = L/sq.root of (Ix/A).
Ix of cross section of column = BD^3/12 ie. 3.25cm^4.
Area of cross section of column = BD ie. 6.25 cm2.
Thus, 300/sq.root of (3.25/6.25) = 416.025.
Ix of cross section of column = BD^3/12 ie. 3.25cm^4.
Area of cross section of column = BD ie. 6.25 cm2.
Thus, 300/sq.root of (3.25/6.25) = 416.025.
Subhankar said:
9 years ago
300 * 2 * √3/2.5 = 415.69.
Anubhav Srivastav said:
9 years ago
Slenderness ratio = le/r(min).
le = 300 ,r(min) = (I/A)^1/2
Ixx = a^4/12= 25^4/12 = 32552 cm^4,
A = 25^2= 625 cm^2.
Rmin = (32552 cm^4/ 625 cm^2)1/2 = 7.21 cm.
Slenderness ratio = 300/7.21= 41.6cm = 416mm.
le = 300 ,r(min) = (I/A)^1/2
Ixx = a^4/12= 25^4/12 = 32552 cm^4,
A = 25^2= 625 cm^2.
Rmin = (32552 cm^4/ 625 cm^2)1/2 = 7.21 cm.
Slenderness ratio = 300/7.21= 41.6cm = 416mm.
Bharat meena said:
9 years ago
Slenderness ratio=le/k.
K=I/A saqur Root
I =bd^3/12.
A =b * d.
I = 2.5 * 2.5^3/12 = 3.255cm^4.
A =2.5*2.5= 6.25cm.
k^2=3.255÷ 6.25 = 0.721.
Slendernes ratio=300÷0.721 = 416.
K=I/A saqur Root
I =bd^3/12.
A =b * d.
I = 2.5 * 2.5^3/12 = 3.255cm^4.
A =2.5*2.5= 6.25cm.
k^2=3.255÷ 6.25 = 0.721.
Slendernes ratio=300÷0.721 = 416.
Kishan said:
9 years ago
Slenderness ratio = left/rmin.
Rmin=I/A for square section a/2*√3=2.5/2√3 = 0.72 leff = 300cm then slenderness is;
= 300/0.72= 416.67ans.
Rmin=I/A for square section a/2*√3=2.5/2√3 = 0.72 leff = 300cm then slenderness is;
= 300/0.72= 416.67ans.
Bikash Kabiraj said:
8 years ago
Slenderness ratio = effective length/radius of gyration.
Radius of gyration = under root of i/a,
i = moment of inertia and a =cross sectionl area. i=2.5^4/12= and a = 2.5^2.
So radius of gyration = 0.721.
Soslenderness ratio=300/0.721 = 416.088.
Radius of gyration = under root of i/a,
i = moment of inertia and a =cross sectionl area. i=2.5^4/12= and a = 2.5^2.
So radius of gyration = 0.721.
Soslenderness ratio=300/0.721 = 416.088.
Ramana panchadi said:
8 years ago
Slenderness ratio=L effective/Kmin.
K=radius of gyration;K=sq root of i/a;i=moment of intertia @ a=cross sectional area.
k=solid circle=d/4,
K=square=a/2 root 3,
Sol:- K=2.5/2 root 3 =0.7122.
Slenderness ratio=300/0.71222=415.69.
K=radius of gyration;K=sq root of i/a;i=moment of intertia @ a=cross sectional area.
k=solid circle=d/4,
K=square=a/2 root 3,
Sol:- K=2.5/2 root 3 =0.7122.
Slenderness ratio=300/0.71222=415.69.
Raj said:
8 years ago
Can anyone answer?
Slender ness ratio of 5m long column effectively held in position at both ends, but not restrained against rotation and having a circular cross section of the diameter of 5 cm is?
Slender ness ratio of 5m long column effectively held in position at both ends, but not restrained against rotation and having a circular cross section of the diameter of 5 cm is?
Manickam said:
8 years ago
Can anyone tell me, The diagram which represents the axial thrust is called?
Debopriyo pal said:
8 years ago
Thanks for the answer.
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