Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 23)
23.
The slenderness ratio of a vertical column of a square cross-section of 2.5 cm sides and 300 cm length, is
Discussion:
33 comments Page 2 of 4.
Jahangir badini said:
7 years ago
Slenderness ratio : L/√bh*3/12/area.
Yamiiiii said:
7 years ago
S.R=Equivalent length of column or unsupported length/least radius of gyration
=Le/k,
=Le/√(I/A).
√[I/A] =root[(2.5/12)*(1/2.5)],
=0.72168783654321698610321.
S.R=300/0.72168783654321698610321.
S.R=415.6921938=415. 69=416.
=Le/k,
=Le/√(I/A).
√[I/A] =root[(2.5/12)*(1/2.5)],
=0.72168783654321698610321.
S.R=300/0.72168783654321698610321.
S.R=415.6921938=415. 69=416.
U Kumar said:
8 years ago
Thanks @Subhankar.
Debopriyo pal said:
8 years ago
Thanks for the answer.
Manickam said:
8 years ago
Can anyone tell me, The diagram which represents the axial thrust is called?
Raj said:
8 years ago
Can anyone answer?
Slender ness ratio of 5m long column effectively held in position at both ends, but not restrained against rotation and having a circular cross section of the diameter of 5 cm is?
Slender ness ratio of 5m long column effectively held in position at both ends, but not restrained against rotation and having a circular cross section of the diameter of 5 cm is?
Ramana panchadi said:
8 years ago
Slenderness ratio=L effective/Kmin.
K=radius of gyration;K=sq root of i/a;i=moment of intertia @ a=cross sectional area.
k=solid circle=d/4,
K=square=a/2 root 3,
Sol:- K=2.5/2 root 3 =0.7122.
Slenderness ratio=300/0.71222=415.69.
K=radius of gyration;K=sq root of i/a;i=moment of intertia @ a=cross sectional area.
k=solid circle=d/4,
K=square=a/2 root 3,
Sol:- K=2.5/2 root 3 =0.7122.
Slenderness ratio=300/0.71222=415.69.
Bikash Kabiraj said:
8 years ago
Slenderness ratio = effective length/radius of gyration.
Radius of gyration = under root of i/a,
i = moment of inertia and a =cross sectionl area. i=2.5^4/12= and a = 2.5^2.
So radius of gyration = 0.721.
Soslenderness ratio=300/0.721 = 416.088.
Radius of gyration = under root of i/a,
i = moment of inertia and a =cross sectionl area. i=2.5^4/12= and a = 2.5^2.
So radius of gyration = 0.721.
Soslenderness ratio=300/0.721 = 416.088.
Kishan said:
9 years ago
Slenderness ratio = left/rmin.
Rmin=I/A for square section a/2*√3=2.5/2√3 = 0.72 leff = 300cm then slenderness is;
= 300/0.72= 416.67ans.
Rmin=I/A for square section a/2*√3=2.5/2√3 = 0.72 leff = 300cm then slenderness is;
= 300/0.72= 416.67ans.
Bharat meena said:
9 years ago
Slenderness ratio=le/k.
K=I/A saqur Root
I =bd^3/12.
A =b * d.
I = 2.5 * 2.5^3/12 = 3.255cm^4.
A =2.5*2.5= 6.25cm.
k^2=3.255÷ 6.25 = 0.721.
Slendernes ratio=300÷0.721 = 416.
K=I/A saqur Root
I =bd^3/12.
A =b * d.
I = 2.5 * 2.5^3/12 = 3.255cm^4.
A =2.5*2.5= 6.25cm.
k^2=3.255÷ 6.25 = 0.721.
Slendernes ratio=300÷0.721 = 416.
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