Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 11)
11.
If the width b and depth d of a beam simply supported with a central load are interchanged, the deflection at the centre of the beam will be changed in the ratio of
Discussion:
14 comments Page 1 of 2.
Rishabh said:
10 years ago
Ratio of old/new will give I new/I old.
Abhash poudel said:
10 years ago
pl^3/48EI = (pl^3.12)/(48E.bd^3).
pl^3/48EI = (pl^3.12)/(48E.db^3).
db^3/bd^3 = (b/d)^2.
pl^3/48EI = (pl^3.12)/(48E.db^3).
db^3/bd^3 = (b/d)^2.
Utsav said:
9 years ago
Why not (d/b)^2?
Himzz the great said:
9 years ago
According to me option C is right, as first we always take I = bd^3/12 and then db^3/12 which gives us the ratio (d/b)^2.
GURUDAS said:
8 years ago
I old /I new.
= db^3/bd^3,
= (b/d)^2.
Because I is at the bottom and it will revers.
= db^3/bd^3,
= (b/d)^2.
Because I is at the bottom and it will revers.
Bhaskar Manna said:
8 years ago
I agree @Himzz. Option C is the right answer.
(1)
Priya said:
8 years ago
I agree @Abhash Poudel.
Neel said:
8 years ago
According to me, Option C is right.
(2)
Rishi said:
7 years ago
Option c is correct. I new/I old should be done because to compute the change.
Deepak Gupta said:
7 years ago
Option D is correct. Because deflection is inversely proportional to I. So, the value is getting after reversing.
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