Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 5 (Q.No. 4)
4.
If the length of a cantilever carrying an isolated load at its free end is doubled, the deflection of the free end will increase by
Discussion:
15 comments Page 1 of 2.
Shweta puri said:
9 years ago
Read the question carefully, they are not telling about length they said if the load at the free end is double it mean W = 2W. The deflection of the free end is WL^3/3EI when we put W = 2w it become1/2 which is not given in the answer but the right answer is 1/2.
Jinish said:
6 years ago
Deflection 1= wl^3/ 3EI and,
If l = 2 then deflection 2 = 8wl^3/3 EI.
So deflection = deflection 1/ deflection 2 = 1/8.
Correction answer is 1/8.
Here, mentioned length is to doubled l = 2l.
If l = 2 then deflection 2 = 8wl^3/3 EI.
So deflection = deflection 1/ deflection 2 = 1/8.
Correction answer is 1/8.
Here, mentioned length is to doubled l = 2l.
SuSHiL THaKuR said:
7 years ago
Right @Aaqib.
But it is not ask about ratio they ask about how much increase in deflection.
So, x1/x2 =1/8,
i.e x2=8x1 (answer).
I hope you understand.
But it is not ask about ratio they ask about how much increase in deflection.
So, x1/x2 =1/8,
i.e x2=8x1 (answer).
I hope you understand.
Ashish Gusain said:
9 years ago
Option B is wrong.
Deflection = Wl.l.l/3EI,
Given that L = 2l,
Then deflection = W.2l.2l.2l/EI,
=> 8x W.l.l.l/3EI.
So option A is right.
Deflection = Wl.l.l/3EI,
Given that L = 2l,
Then deflection = W.2l.2l.2l/EI,
=> 8x W.l.l.l/3EI.
So option A is right.
Shraddha said:
10 years ago
Answer: 8 times.
Deflection at the free end due to point load = Wl*L*L/3EI.
Put 2L in place of L, it becomes 8 times.
Deflection at the free end due to point load = Wl*L*L/3EI.
Put 2L in place of L, it becomes 8 times.
Aaqib said:
7 years ago
Wl^3÷3Ei÷w (2l) ^3÷3Ei,
=1/8 Answer.
I think option B, please correct me if I m wrong.
=1/8 Answer.
I think option B, please correct me if I m wrong.
Don Dai said:
9 years ago
More W & L, more deflection.
More B & D, less Deflection.
That's why 8 times.
More B & D, less Deflection.
That's why 8 times.
(2)
Baloch said:
9 years ago
It's not doubling the load, it's doubling the length.
L^3, 2L^3 = 8, And is C.
L^3, 2L^3 = 8, And is C.
Dhru said:
5 years ago
Wl^3/3EI upon W(2l^3) /3EI.
Solve then the answer will be 1/8.
Solve then the answer will be 1/8.
(1)
Vishal Amit Patil said:
6 years ago
@All.
Here, it is mentioned to double the load not length.
Here, it is mentioned to double the load not length.
(1)
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