Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 11)
11.
A uniform girder simply supported at its ends is subjected to a uniformly distributed load over its entire length and is propped at the centre so as to neutralise the deflection. The net B.M. at the centre will be
WL
Discussion:
37 comments Page 3 of 4.
Anoop said:
8 years ago
Can anyone tell how reactions are 3wl/16 on each end?
Roy said:
8 years ago
Thanks @Asif.
Bhupendra singh said:
8 years ago
It should be WL^2/32.
Babypriyadarshini said:
8 years ago
I am not understanding it. Please, anyone explain it.
Nikhil said:
8 years ago
I don't understand how to solve this. Please help me.
Civil said:
8 years ago
@Ram.
The equation will be wL^2/32. Substitute W=wL, Final equation will be WL/32.
The equation will be wL^2/32. Substitute W=wL, Final equation will be WL/32.
Rayudu said:
8 years ago
Please, give me the clear explanation.
RAM said:
9 years ago
It must be (WL^2) /32.
Honey said:
9 years ago
its in Kn, not in kn/m2
So W=wl that's why answer is Wl/32.
So W=wl that's why answer is Wl/32.
Naren said:
9 years ago
Please give me the clear explanation.
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