Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 19)
19.
The ratio of the maximum deflections of a beam simply supported at its ends with an isolated central load and that of with a uniformly distributed load over its entire length, is
1
Discussion:
24 comments Page 2 of 3.
Prasanth said:
8 years ago
But some books said 5/8, they took udl deflection divided by point load deflection.
Ezaaz Ahmed said:
8 years ago
Maximum Deflection at the mid-span of a SSB with an isolated central load is WL3/48EI--> i
Maximum deflection at the mid-span of a SSB with UDL through the entire span is 5WL3/384EI--> ii.
i/ii=8/5.
So the correct answer is 8/5.
Maximum deflection at the mid-span of a SSB with UDL through the entire span is 5WL3/384EI--> ii.
i/ii=8/5.
So the correct answer is 8/5.
(1)
Kallan said:
8 years ago
8/5 = 1.6,
24/15 = 1.6,
Both are same.
24/15 = 1.6,
Both are same.
Shubham said:
8 years ago
The answer is 8L/5.
Indu said:
8 years ago
How 24/15 is correct, could you explain me please clearly?
Nikhil said:
8 years ago
24/15 is equal to 8/5 so 24/15 is correct answer.
Jyothi said:
8 years ago
Max Deflection where occurs in the middle only. At supports, it is zero so 8/5 is the answer. But why 24/15?
Vicky said:
8 years ago
Question is asking max deflection at ends and these formulas are for max deflection at centre.
Clear it please.
Clear it please.
Sanjeev kumar said:
9 years ago
Answer is 8/5. Why we need to multiply the factor 3?
Manoranjan said:
9 years ago
I am not getting this, Please, Properly discuss this question.
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