Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 41)
41.
The section modulus of a rectangular section is proportional to
Discussion:
21 comments Page 2 of 3.
Jaz said:
6 years ago
Z=I/Y and I=AK^2.
So, that z proportional to area and radius of Gyration.
So, that z proportional to area and radius of Gyration.
Roshan said:
7 years ago
Z=I/y, I = the second moment of area = Ai*yi.
Z=(Ai*yi)/y.
Z proportional to the summation of the area of the element.
Z=(Ai*yi)/y.
Z proportional to the summation of the area of the element.
Jimmy said:
1 decade ago
How? As per calculation it is A*d/6. Answer should be C.
Sehra said:
8 years ago
Z=I/y max=bd^2 /6
Z=Ad/6 A=bit
Z-A or Z- d.
Z=Ad/6 A=bit
Z-A or Z- d.
Thebaloch said:
8 years ago
S = m/z
Z = M/S
S = F/A
So Z=AM/F.
So, A is correct.
Z = M/S
S = F/A
So Z=AM/F.
So, A is correct.
Baloch said:
9 years ago
E seems right,
The second moment of area of rectangular sec = bh^3 / 12 , and its Z = bh^2/6 (half).
The second moment of area of rectangular sec = bh^3 / 12 , and its Z = bh^2/6 (half).
Yogesh said:
9 years ago
Z = bd^2/6.
Z ^ bd^2.
Z^(bd) x (d).
Z ^ (Area) x (Depth).
Answer should be 'C'.
Z ^ bd^2.
Z^(bd) x (d).
Z ^ (Area) x (Depth).
Answer should be 'C'.
Suwami said:
9 years ago
Z = I/y = Ak2/y.
Rakesh kumar sah said:
9 years ago
Section modulus = Z/A.
Hence option A is correct.
Hence option A is correct.
S s said:
9 years ago
You are right @Jimmy, its bd2/6.
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