Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 41)
41.
The section modulus of a rectangular section is proportional to
Discussion:
21 comments Page 2 of 3.
Shivkumar said:
7 years ago
You are right @Sumit.
The answer will be A.
The answer will be A.
Roshan said:
7 years ago
Z=I/y, I = the second moment of area = Ai*yi.
Z=(Ai*yi)/y.
Z proportional to the summation of the area of the element.
Z=(Ai*yi)/y.
Z proportional to the summation of the area of the element.
Jaz said:
6 years ago
Z=I/Y and I=AK^2.
So, that z proportional to area and radius of Gyration.
So, that z proportional to area and radius of Gyration.
Nicks said:
6 years ago
If axis changees be Ix or Iy section modules will change.
So, be it bd2/6 or b2d/6. Section modulus will be proportional to 1/6 * area* depth. So C must be the correct answer.
So, be it bd2/6 or b2d/6. Section modulus will be proportional to 1/6 * area* depth. So C must be the correct answer.
(3)
Prashant said:
6 years ago
In option A, C and D. Area is common and its product with depth and width gives the section modulus, depending upon the axis in consideration. So, AREA is common is all possible options. That's why option A is correct.
(6)
Amjad Ali said:
6 years ago
Yes, agree. C is the correct Answer.
(1)
Suman said:
5 years ago
Thanks @Shubam.
Manojkumar Rajendran said:
3 years ago
They didn't mention section modulus about which axis.
So, it may be about c.g or base or any axis.hence general for z=A.x and z=A.x^2 hence it is proportional to Area. Therefore, Answer A is correct.
So, it may be about c.g or base or any axis.hence general for z=A.x and z=A.x^2 hence it is proportional to Area. Therefore, Answer A is correct.
Sonu (Guruji) said:
3 years ago
Agree, the right Answer should be A.
Mian Khan said:
8 months ago
Correct option is (C) product of the area and depth
The section modulus (Z) of a rectangular section is proportional to the product of the area and depth. Here's why:
Z = (b * d²) / 6, A = b * d.
Z = (b * d) * (d/6) = A * (d/6).
This shows that the section modulus (Z) is directly proportional to the area (A) multiplied by the depth (d) divided by 6. Since 6 is a constant, we can say Z is proportional to A * d.
The section modulus (Z) of a rectangular section is proportional to the product of the area and depth. Here's why:
Z = (b * d²) / 6, A = b * d.
Z = (b * d) * (d/6) = A * (d/6).
This shows that the section modulus (Z) is directly proportional to the area (A) multiplied by the depth (d) divided by 6. Since 6 is a constant, we can say Z is proportional to A * d.
(2)
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