Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 4 (Q.No. 41)
41.
The section modulus of a rectangular section is proportional to
area of the section
square of the area of the section
product of the area and depth
product of the area and width
half moment of inertia of the section.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
21 comments Page 2 of 3.

Shivkumar said:   7 years ago
You are right @Sumit.

The answer will be A.

SHubam said:   7 years ago
Correct answer is A. Depending upon the axis which you are taking for calculation whether it is Ix or Iy. Depth & width changes but the area remains same. In simple language,

Ix= product of area n depth.
Iy = product of area n width.

Hence in this question. Axis is not given. So Z will change with the change of I. But area remains same in both the conditions.
(7)

Sehra said:   8 years ago
Z=I/y max=bd^2 /6
Z=Ad/6 A=bit
Z-A or Z- d.

Thebaloch said:   8 years ago
S = m/z
Z = M/S
S = F/A

So Z=AM/F.
So, A is correct.

Baloch said:   9 years ago
E seems right,

The second moment of area of rectangular sec = bh^3 / 12 , and its Z = bh^2/6 (half).

Yogesh said:   9 years ago
Z = bd^2/6.

Z ^ bd^2.
Z^(bd) x (d).
Z ^ (Area) x (Depth).

Answer should be 'C'.

Suwami said:   9 years ago
Z = I/y = Ak2/y.

Rakesh kumar sah said:   9 years ago
Section modulus = Z/A.

Hence option A is correct.

RANJAN PATRA said:   9 years ago
Answer should be option C.

S s said:   9 years ago
You are right @Jimmy, its bd2/6.


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