Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 29)
29.
The ratio of the moment of inertia of a circular plate and that of a square plate for equal depth, is
Answer: Option
Explanation:
For circular plate, MI = π*d^4/64.
For square plate, MI = d^4/12.
So, Ratio = MI of circular plate/MI of square plate.
= 3*π/16.
Discussion:
6 comments Page 1 of 1.
Amarjreet kumar said:
6 years ago
According to me, A is the right option.
(1)
Gnanasundar said:
7 years ago
The Answer should be 3π/16.
M.O.I of circular=πD^4/64,
M. O. I of rectangular=D^3/12,
But here depth is given equal so M. O. I of rec=D^4/12,
Circular/rectangular =3π/16.
M.O.I of circular=πD^4/64,
M. O. I of rectangular=D^3/12,
But here depth is given equal so M. O. I of rec=D^4/12,
Circular/rectangular =3π/16.
PARMANAND PRASAD said:
7 years ago
Both A and D is correct.
(1)
Roop Kumar said:
7 years ago
Both options D & A are correct.
Himzz said:
9 years ago
According to me, it seems option A is also right.
Abhay said:
10 years ago
For circular plate Moment of inertia Ic = πD^4/64.
For square plate Moment of inertia is = D^4/12.
Ratio = (πD^4/64)/( D^4/12) => 3π/16.
For square plate Moment of inertia is = D^4/12.
Ratio = (πD^4/64)/( D^4/12) => 3π/16.
(1)
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