Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 18)
18.
For a cantilever with a uniformly distributed load W over its entire length L, the maximum bending moment is
WL
WL
WL W2L WL2Discussion:
14 comments Page 1 of 2.
Durlavi said:
5 years ago
WL^2/2 is correct.
(4)
Nishant said:
8 years ago
1.For simply supported Mmax=Wl/4, R=W/2.
2.For simply supported with eccentric point load M.ax= Wab/l , Ra= Wb/2, Rb= Wa/2.
3.For a simply supported beam with UDL on entire span Mmax= wl^2/8 , R= Wl/2.
4. For. Cantilever beam with point load at end
Mmax= W.L.
5.For cantilever beam with UDL on entire span
Mmax= wl^2/2.
2.For simply supported with eccentric point load M.ax= Wab/l , Ra= Wb/2, Rb= Wa/2.
3.For a simply supported beam with UDL on entire span Mmax= wl^2/8 , R= Wl/2.
4. For. Cantilever beam with point load at end
Mmax= W.L.
5.For cantilever beam with UDL on entire span
Mmax= wl^2/2.
(1)
Shivu Rathod said:
7 years ago
@Sai Madhav.
Max b.m for cantilever UDL is algebraic sum of moment i.e wl*l/2 =wl2/2.
Max b.m for cantilever UDL is algebraic sum of moment i.e wl*l/2 =wl2/2.
(1)
Pradipto Sarkar said:
7 years ago
The given answer is correct.
Max bending moment will be;
=wL^2/2.
also =WL/2.
Where weight per length(w) = Weight(W)/length.
Max bending moment will be;
=wL^2/2.
also =WL/2.
Where weight per length(w) = Weight(W)/length.
(1)
Sajjad ali said:
9 years ago
I think the answer is WL^2/2.
Baloch said:
9 years ago
The answer must be Wl2/2.
Vijaysingh jadhav said:
9 years ago
It is WL/2 because in the question they have total UDL of magnitude W Hence WL/2 otherwise if w kg/m if they had mentioned then it would be wlxl/2 i.e. Wl2/2.
Raj said:
9 years ago
Answer should be wl^2/2.
Pk050 said:
8 years ago
According to me, it is Wl^2/8.
Anil said:
8 years ago
@Pk050.
wl^2/8 is for max deflection not for max BM.
wl^2/8 is for max deflection not for max BM.
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