Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 20)
20.
The shape of the bending moment diagram over the length of a beam, carrying a uniformly distributed load is always
Discussion:
5 comments Page 1 of 1.
Pradhyumna said:
1 decade ago
In case of BM diagram for:
Point load = linear shape.
UDL = parabolic shape.
UVL = cubical shape.
Point load = linear shape.
UDL = parabolic shape.
UVL = cubical shape.
Nikhil said:
1 decade ago
Proof:
The parabolic equation is Y = mx^2.
The B.M for simply supported beam subjected to u.d.l over all span. is
WL^2/8.
Since the square variation shows the parabola.
The parabolic equation is Y = mx^2.
The B.M for simply supported beam subjected to u.d.l over all span. is
WL^2/8.
Since the square variation shows the parabola.
Kavya said:
1 decade ago
SF diagram for UDL is linear.
BM diagram for UDL is 2nd degree Parabola.
BM diagram for UDL is 2nd degree Parabola.
(1)
Viru kapoor said:
7 years ago
BM diagram is parabolic and sheer force is linear.
(2)
Achintya said:
3 years ago
Point load = linear (1st degree).
UDL = parabolic shape (2nd degree).
UVL = cubical shape (3rd degree).
UDL = parabolic shape (2nd degree).
UVL = cubical shape (3rd degree).
(4)
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