Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 11)
11.
A simply supported beam of span L carries a uniformly distributed load W. The maximum bending moment M is
Discussion:
18 comments Page 1 of 2.
Naveed Ahmad said:
4 years ago
Its W*L^2/8.
(2)
Ali said:
5 years ago
It should be Wl^2/8.
(1)
Akash said:
5 years ago
The correct answer is WL/8.
See the W is capital that means total load.
In these types of cases, W represents total load.
But we know the maximum bending moment is wl^2/8.
These cases w=W where w is udl intensity and W is a total load.
Thanks.
See the W is capital that means total load.
In these types of cases, W represents total load.
But we know the maximum bending moment is wl^2/8.
These cases w=W where w is udl intensity and W is a total load.
Thanks.
(1)
Sheela KR said:
7 years ago
Agree @Kallan.
Rakesh yadav said:
2 years ago
Agree, the right answer is WL/8.
Kaku said:
4 years ago
The Correct answer is wl^2/8.
Faruque said:
6 years ago
It should said that total uniformly distributed load is W.
Apoorva kumar said:
6 years ago
Wl/2 is the correct one.
Avinash said:
7 years ago
Thanks for explaining @Mounika Reddy.
Mounika reddy said:
1 decade ago
Support reactions are Vay = wl/2 = Vby.
Cut s/n and take the moment at pont zero.
M = - (wx^2/2) +wlx/2.
Max moment at mid pnt l/2.
M = Wl^2/8.
For uniformly distributed load moment varies parabolically not linearly.
Cut s/n and take the moment at pont zero.
M = - (wx^2/2) +wlx/2.
Max moment at mid pnt l/2.
M = Wl^2/8.
For uniformly distributed load moment varies parabolically not linearly.
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