Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 20)
20.
If Z and I are the section modulus and moment of inertia of the section, the shear force F and bending moment M at a section are related by
Discussion:
9 comments Page 1 of 1.
Sandeep Kumar said:
5 years ago
Here, F is given as shear force not bending stress so M/I=F/y formula is invalid. So, the correct answer will be the rate of change of moments is shear force i.e option C.
(2)
Tushar patel said:
6 years ago
Bending equation, M/I = F/Y = E/R.
M = FI/Y.
z = I/Y.
So M=F*Z.
And F=M/Z.
So A and B both the correct answer
M = FI/Y.
z = I/Y.
So M=F*Z.
And F=M/Z.
So A and B both the correct answer
(1)
Nirmalya said:
8 years ago
Answer should be A.
M/I = f/y.
F=M.y/I.
M/I = f/y.
F=M.y/I.
Navneet said:
8 years ago
It's sf not shear stress.
Protap said:
7 years ago
Explain the answer.
Manu said:
7 years ago
The Rate of change of B.M is a shear force.
Amol Ghuge said:
6 years ago
Rate of change of bending moment is SF. So, the Correct answer is C.
VIPIN SAINATH said:
5 years ago
The rate of change of the Bending Moment (M) along the length = to Shear Force (V),.
Shear, Tou = (dM/dx) x Q / Ib. where Shear Force, V = dM/dx.
So, Finally,
Tou = VQ / Ib.
Shear, Tou = (dM/dx) x Q / Ib. where Shear Force, V = dM/dx.
So, Finally,
Tou = VQ / Ib.
Puja Sonar said:
5 years ago
Rate of change of bending moment with respect to distance is called shear force so dM/dx= F.
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