Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 37)
37.
The ratio of the tensile stress developed in the wall of a boiler in the circumferential direction to the tensile stress in the axial direction, is
Discussion:
6 comments Page 1 of 1.
Vinod said:
10 years ago
Circumferential Tensile stress in a boiler is, sigma = (P.d)/(2t)----1.
Axial Tensile stress in a boiler is, sigma = (P.d)/(4t)----2.
Now the ratio is = (Equation 1)/(Equation 2).
Answer: 2.
Axial Tensile stress in a boiler is, sigma = (P.d)/(4t)----2.
Now the ratio is = (Equation 1)/(Equation 2).
Answer: 2.
(1)
Suraj giri said:
7 years ago
Thanks @Vinod.
Protap said:
7 years ago
Thanks for the answer @Vinod.
Nilraj said:
7 years ago
Thanks for the answer @Vinod.
Amu bokato said:
6 years ago
Thanks for explaining the answer @Vinod.
JEET said:
5 years ago
Circumferential Tensile stress in a boiler is, sigma = (P.d)/(2t) - (equation 1).
Axial Tensile stress in a boiler is, sigma = (P.d)/(4t) - (equation 2).
Now, the ratio is = (Equation 1)/(Equation 2).
Answer is = 2.
Axial Tensile stress in a boiler is, sigma = (P.d)/(4t) - (equation 2).
Now, the ratio is = (Equation 1)/(Equation 2).
Answer is = 2.
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