# Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 4 (Q.No. 40)

40.

If the stress produced by a prismatic bar is equal to the working stress, the area of the cross-section of the prismatic bar, becomes

Discussion:

15 comments Page 1 of 2.
Aashish Tiwari said:
11 months ago

Here working stress applied is equal to stress produced in the prismatic bar.

So, the resultant stress becomes zero and we have

Stress =force/area.

Area = force/stress = force/0 = infinite.

So, the resultant stress becomes zero and we have

Stress =force/area.

Area = force/stress = force/0 = infinite.

(2)

M. Waseem said:
2 years ago

The Given Answer is Correct.

Explanation:

as we know that stress= Îµ*E

or P/A = Îµ* E

or A = P/Îµ*E.

Now if working stress equals the stress in the bar then the strain (Îµ) will be zero, and according to the above equation when strain is zero then Area becomes Infinite.

A = P/0*E

A = Infinite.

Explanation:

as we know that stress= Îµ*E

or P/A = Îµ* E

or A = P/Îµ*E.

Now if working stress equals the stress in the bar then the strain (Îµ) will be zero, and according to the above equation when strain is zero then Area becomes Infinite.

A = P/0*E

A = Infinite.

(3)

B.Nehru said:
4 years ago

Yes, you are right, Thanks @Jay Brahmabhatt.

Ankit namdev said:
4 years ago

Minumum is correct one.

Khurshid said:
5 years ago

I think area has to e infinite when stress is maximum in order to avoid unwanted situation.

(1)

Hemraj Basnet said:
5 years ago

Consider S = stress.

Then partial derivative of stress with respect area.

dS/dA=pd(A power minus 1)/dA,

solve it,

A=p/0,

A= infinite.

Then partial derivative of stress with respect area.

dS/dA=pd(A power minus 1)/dA,

solve it,

A=p/0,

A= infinite.

Neel said:
6 years ago

Freely prismatic bar stress is equal zero. So area is infinite.

Satya said:
6 years ago

Option D is correct I think.

Skm said:
6 years ago

Option D is correct.

Deepak kumar said:
6 years ago

Working stress means maximum so the area will be minimum.

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