Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 2 (Q.No. 39)
39.
A solid cube is subjected to equal normal forces on all its faces. The volumetric strain will be x-times the linear strain in any of the three axes when
x = 1
x = 2
x = 3
x = 4
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

W khan said:   3 years ago
Equal normal forces are acting on all faces of the cube, so strain will be equal in all directions(ϵx = ϵy = ϵz).

ϵv = ϵx + ϵy + ϵz
ϵv = 3ϵx

Hence, the Volumetric strain is 3 times the strain in all directions.

Gopi Sunkari said:   4 years ago
Very thanks for the explanation.

Balram said:   5 years ago
Ε (ν) =ε (χ) +ε (γ) +ε (z).
As σ is the same everywhere.
Ε (ν) =3ε (γ).
Χ=3.

XYZ said:   6 years ago
The volumetric strain is the change in dimension in three directions and the linear strain depends on the change in only one direction so the volumetric strain is 1 times the linear strain in any of the three directions.

Asita said:   6 years ago
Thanks @Rohit.

Rohit said:   9 years ago
Here, dV/v = 3 * (sigma/E * (1 - 2/m)).
It is 3 times because cube is subjected to 3 mutually perpendicular stresses.

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