Civil Engineering - Steel Structure Design - Discussion
Discussion Forum : Steel Structure Design - Section 1 (Q.No. 16)
16.
The equivalent axial tensile load Pe, which produces an average axial tensile stress in the section equivalent to the combined stress due to axial tension P and bending M, at the extreme fibre of the section, is given by (where Z is the section modulus of the section).
Discussion:
5 comments Page 1 of 1.
Harsh said:
8 years ago
If there is combine stress.
Then Pe=P/A+Mxx.Y/Ixx.
And if there is an equivalent axial load for uniaxial bending.
Then Pe= P+ MA/Z.
Then Pe=P/A+Mxx.Y/Ixx.
And if there is an equivalent axial load for uniaxial bending.
Then Pe= P+ MA/Z.
(1)
Pramit Samanta said:
5 years ago
Given Answer is right.
The first component is due to the direct load.
The second one is due to bending compression.
The first component is due to the direct load.
The second one is due to bending compression.
Ganesh said:
10 years ago
Equivalent axial load = p+b*m.
Sunny said:
9 years ago
It should be p/a+ m/z.
DHARMENDRA KUMAR MAURYA said:
8 years ago
It is P/A-M/Z.
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