Civil Engineering - Steel Structure Design - Discussion

39. 

If f is the maximum allowable bending stress in a tension member whose radius of gyration is r and depth is 2y, the required cross sectional area A is given by

[A].
[B].
[C].
[D].
[E].

Answer: Option A

Explanation:

No answer description available for this question.

Kush said: (Sep 20, 2016)  
Pure bending equation:

(F/Ymax) = (M/I) = (E/R).

Put,
Ymax = 2y/2 = y.
I = Ar^2 in the above equation.
Then we get the answer A.

Chhaya said: (Apr 28, 2017)  
F/Y = M/I,
F = MY/I,
r = sqrt I/A,
I = Ar2.

By substituting the values, you will get the answer.

Arifkhan said: (Apr 14, 2020)  
We have: F=My/I.
Also, I=√(I/A)=> I= r^2*A.
Now F =My/r^2*A => A= My/fr^2.

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