Civil Engineering - Steel Structure Design - Discussion
Discussion Forum : Steel Structure Design - Section 2 (Q.No. 43)
43.
For eccentrically loaded columns, the bending factor is
Discussion:
7 comments Page 1 of 1.
Harry said:
4 years ago
C is correct. Agree with thee given answer.
ASHISH SHARMA said:
5 years ago
D is the correct answer.
POOJA said:
6 years ago
M/I = f/y
f = M X y/I
= M /Z
Load = M * A/Z so answer is C.
f = M X y/I
= M /Z
Load = M * A/Z so answer is C.
Uttudon said:
7 years ago
Z/A is the correct answer. So, Option D is correct.
Garry said:
8 years ago
I totally agree @ Raj the correct answer should be option d.
Michael said:
9 years ago
What is the right answer anyone know?
Raj said:
1 decade ago
We know M/I = F/y.
So M = F*Z, Z section modulus. Therefore we can write M = P*(Z/A).
May be answer is D.
So M = F*Z, Z section modulus. Therefore we can write M = P*(Z/A).
May be answer is D.
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