Civil Engineering - Steel Structure Design - Discussion

Discussion Forum : Steel Structure Design - Section 4 (Q.No. 30)
30.
If the area of cross-section of a single angle discontinuous strut is 30 cm2 and allowable working stress corresponding to its slenderness ratio is 625 kg/cm2, the safe load carrying capacity of the member, is
10 tonnes
12 tonnes
15 tonnes
18 tonnes
20 tonnes
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 2 of 2.

Amit kr mondal said:   6 years ago
As it is a single angle discontinuous strut so the effective area is calculated by
k= 3A1 /(3A1 +A2).

Where A1, A2= Area of connected leg and unconnected (outstand) leg.

Here A1 =A2 = 30/2 =15 (Here all data are not given so we assume both leg having equal area)
hence k=0.75 (by calculation).

So load carrying capacity= k*A*S = 0.75 * 30 * 625 = 14062.5 Kg = 14.062 toones i.e 15 tonnes (nearby value).


Post your comments here:

Your comments will be displayed after verification.