Civil Engineering - Steel Structure Design - Discussion
Discussion Forum : Steel Structure Design - Section 1 (Q.No. 12)
12.
The critical load for a column of length I hinged at both ends and having flexural rigidity El, is given by
none of these
Discussion:
2 comments Page 1 of 1.
KRISHAN SHARMA said:
7 years ago
The critical load =(π^2xEI)/(KL)^2.
Given condition KL = L.
Given condition KL = L.
Rishi R said:
10 years ago
Fixed - fixed E.L = L\2.
Fixed - hinged E.L = L\1.414.
Hinged - hinged E.L= L.
Fixed - free E.L = 2L.
P = ((pi)^2 x EI)/(E.L)^2.
P = Crushing load.
Pi = 22/7.
E = Young's modulus.
I = Moment of inertia.
E.L = Effective length.
L = Unsupported length.
For any condition calculate on your own by this formula.
Fixed - hinged E.L = L\1.414.
Hinged - hinged E.L= L.
Fixed - free E.L = 2L.
P = ((pi)^2 x EI)/(E.L)^2.
P = Crushing load.
Pi = 22/7.
E = Young's modulus.
I = Moment of inertia.
E.L = Effective length.
L = Unsupported length.
For any condition calculate on your own by this formula.
(1)
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