Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 41)
41.
A stratum of clay 2 m thick will get consolidated 80% in 10 years. For the 80% consolidation of 8 m thick stratum of the same clay, the time required is
Discussion:
10 comments Page 1 of 1.
Farheena Firdousi said:
5 years ago
Thanks @Abhay.
Jilile said:
6 years ago
Thanks @Abhay.
Puspendu said:
7 years ago
Thanks for the given explanation @Abhay.
(2)
Karan Panjabi said:
7 years ago
Thanks for the solution @Abhishek.
Deepak Baswal said:
7 years ago
Thanks for the given explanation @Abhay.
Anant said:
8 years ago
Drainage path will be 4 times.
(t1/t2) = sq(d1)/sq(d2).
t1 = sq(4)*10/sq(1).
t1 = 160 yrs.
(t1/t2) = sq(d1)/sq(d2).
t1 = sq(4)*10/sq(1).
t1 = 160 yrs.
(1)
Abhishek Nandi said:
8 years ago
Since the percentage of consolidation is same. using this formula fetches you the solution.
T1/T2=[(D2)^2] / [(D1)^2].
T=time taken to consolidate a stratum of soil of thickness D,
T1/10=[(8)^2] / [(2)^2)],
T1=10*64/4=160.
T1/T2=[(D2)^2] / [(D1)^2].
T=time taken to consolidate a stratum of soil of thickness D,
T1/10=[(8)^2] / [(2)^2)],
T1=10*64/4=160.
(5)
Muhannad said:
9 years ago
.8 x 10/1 = 8.
tv = 8.
.8 x t/16 = 8.
t = 160.
tv = 8.
.8 x t/16 = 8.
t = 160.
(1)
Abhay said:
9 years ago
Time factor T = Cv*t/h^2.
T = 80*10/2^2 = 200.
For h= 8 m.
T = 80*t/8^2 => 200*64/80 = t.
=> t = 160 years.
T = 80*10/2^2 = 200.
For h= 8 m.
T = 80*t/8^2 => 200*64/80 = t.
=> t = 160 years.
(15)
Deep said:
1 decade ago
Tv = Cvt/d2.
Cv*10/4 = cv*t/64.
T = 160 years.
Cv*10/4 = cv*t/64.
T = 160 years.
(3)
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