Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 25)
25.
A moist soil sample of volume 60 cc. weighs 108 g and its dried weight is 86.4 g. If its absolute density is 2.52, the degree of saturation is
Discussion:
15 comments Page 1 of 2.
Umar habib said:
3 years ago
Step1) bulk density(yb)= W/V=108/60 = 1.8.
Step2) dry density (yd)=Wd/V=86.4/60 = 1.44.
Step3) water content determination(w).
Yd=Yb/1+w.
So 1.44= 1.8/1+w,
So 1+w = 1.8/1.44,
So w = (1.8/1.44)-1,
So, w= 1.25-1= o.25,
w = 0.25.
Step4) void ratio determination;
Yd=G.Yw/1+e,
1.44= 2.52/1+e,
e= (2.52/1.44)-1,
e= 0.75.
Step5) degree of saturation determination(SR)
SR= WG/e.
Sr= 0.25 * 2.52/0.75,
Sr= 0.84,
Sr= 84%.
So, the answer is 84%.
Step2) dry density (yd)=Wd/V=86.4/60 = 1.44.
Step3) water content determination(w).
Yd=Yb/1+w.
So 1.44= 1.8/1+w,
So 1+w = 1.8/1.44,
So w = (1.8/1.44)-1,
So, w= 1.25-1= o.25,
w = 0.25.
Step4) void ratio determination;
Yd=G.Yw/1+e,
1.44= 2.52/1+e,
e= (2.52/1.44)-1,
e= 0.75.
Step5) degree of saturation determination(SR)
SR= WG/e.
Sr= 0.25 * 2.52/0.75,
Sr= 0.84,
Sr= 84%.
So, the answer is 84%.
(9)
Romi said:
3 years ago
A partially saturated sample of soil has a volume of 60 cc and a mass of 92g. The sample is dried in an oven and its dried mass is 73.8g. If the specific gravity of solids be 2.62.
Sind the degree of saturation, water content, void ratio, porosity, bulk unit weight and dry unit weight.
Sind the degree of saturation, water content, void ratio, porosity, bulk unit weight and dry unit weight.
(1)
Geet said:
4 years ago
@Kishan.
Very nice, Thanks.
Very nice, Thanks.
(1)
Kataki said:
5 years ago
Mass of water=108-86.4 g =21.6 g.
Volume of water=21.6/1 cc=21.6cc.
Now, Mass of dried soil =86.4g and absolute density =2.52.
Therefore Volume of soil solids = 86.4/2.52=34.29cc.
Also, Total volume is given = 60cc.
Hence volume of air =60-(34.29+21.6) cc = 4.11 cc.
Volume of voids = 4.11 + 21.6 = 25.71 cc.
Thus Degree of Saturation =Vol. of water/Vo/. of voids *100=21.6/25.71*100=84%.
Volume of water=21.6/1 cc=21.6cc.
Now, Mass of dried soil =86.4g and absolute density =2.52.
Therefore Volume of soil solids = 86.4/2.52=34.29cc.
Also, Total volume is given = 60cc.
Hence volume of air =60-(34.29+21.6) cc = 4.11 cc.
Volume of voids = 4.11 + 21.6 = 25.71 cc.
Thus Degree of Saturation =Vol. of water/Vo/. of voids *100=21.6/25.71*100=84%.
(6)
Wakas said:
5 years ago
@Balvinder.
Even if the absolute density is given, we get relative density by dividing it by density of water which is in our case 1g/cc and absolute density should have been 2.52 g/cc.
It should have been Relative Density instead of absolute density.
Even if the absolute density is given, we get relative density by dividing it by density of water which is in our case 1g/cc and absolute density should have been 2.52 g/cc.
It should have been Relative Density instead of absolute density.
Balvinder said:
6 years ago
How you guys are taking G=2. 52?
Please explain.
Please explain.
Joti said:
6 years ago
Thanks @Bhaskar.
Jonty said:
7 years ago
Well said Thanks @Abhay.
Anomie said:
7 years ago
Thanks for the explanation @Anand Joshi.
Shashank said:
8 years ago
The Critical hydraulic gradient (i) = G-1/(1+e).
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