Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 5 (Q.No. 22)
22.
A structure is erected on an impervious clay whose thickness is 12 m. Drainage is possible both at upper and lower surfaces. Coefficient of consolidation is 0.015 cm2 per minute. For attaining 50% consolidation with a time factor 0.20, the number of days required
Discussion:
16 comments Page 2 of 2.
Santhu said:
8 years ago
According to me, 3333.33 days is correct.
Apcivilian said:
9 years ago
Nice explanation @Bhargavi.
Abhay said:
10 years ago
Time factor T = Cv*t/H^2.
Where Cv = coeff. of consolidation cm^2/min.
t = time in min.
H = Thickness of soils sample.
Therefore,
t= T * H^2/Cv.
For double drainage H = 1200/2 = 600 cm.
t = 0.2 * (600^2)/(0.015) = 4800000 min.
t = 4800000/(24*60)days.
t = 3333.3333 days.
Where Cv = coeff. of consolidation cm^2/min.
t = time in min.
H = Thickness of soils sample.
Therefore,
t= T * H^2/Cv.
For double drainage H = 1200/2 = 600 cm.
t = 0.2 * (600^2)/(0.015) = 4800000 min.
t = 4800000/(24*60)days.
t = 3333.3333 days.
(3)
Bhargavi said:
1 decade ago
Tv = Cv*t/d^2 (here d is double drainage so d/2).
d = 12/2 = 6 m = 600 cm.
Cv = 0.015 cm^2/min.
Tv = 0.2 (time factor).
So, t = Tv*d^2/Cv.
= 0.2*(600)^2/0.015.
= 48*10^5 cm^2/min.
= 48*10^5/(24*60).
= 3333.33 days.
d = 12/2 = 6 m = 600 cm.
Cv = 0.015 cm^2/min.
Tv = 0.2 (time factor).
So, t = Tv*d^2/Cv.
= 0.2*(600)^2/0.015.
= 48*10^5 cm^2/min.
= 48*10^5/(24*60).
= 3333.33 days.
(2)
Ramakrishna said:
1 decade ago
Tv = Cv*t/d^2 = (0.015*24*60)*0.2/(12*100)^2 = 333333.3333.
CH SWAMY said:
1 decade ago
Tv = Cv/t/H^2.
t = 0.2*12*12*100*100/(0.015*60*24) days = 13333.33 days.
t = 0.2*12*12*100*100/(0.015*60*24) days = 13333.33 days.
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