Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 15)
15.
If dry density, water density and specific gravity of solids of a given soil sample are 1.6 g/cc, 1.84 g/cc and 2.56 respectively, the porosity of the soil sample, is
0.375
0.370
0.380
0.390
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
30 comments Page 1 of 3.

Karan said:   1 year ago
Given,
Dry density = 1.69g/cc
Density of water=1.84g/cc
Specific Gravity of solids=2.56
The porosity of the Soil sample =?

We know that,
Dry density = (specific gravity * density of water )/(1+e).
1.6 = (2.56*1.84)/(1+e).
=>1.6=4.7104/(1+e).
=> (4.7104-1.6) = 1.6e.
=> e= 3.1104/1.6
so e = 1.944
Now,
n= e/(1+e).
or, n= 1.944/(1+1.944).
n = 0.66 .

As per the given problem, the Porosity of the given solid is 0.66.
But, 0.66 isn't available in the option.

Now try out this way ;
Usually, we take the density of water as 1g/cc or 1000kg/m^3
Let's input density of water is equal to 1 g/cc then,
Dry density = (specific gravity *density of water )/(1+e)
1.6=(2.56*1)/(1+e)
=> 1.6=2.56/(1+e)
=>, 2.56-1.6=1.6e
=> 0.96=1.6e
e= 0.96/1.6.
It gives the value of void ratio e= 0.6.
and we can easily find out the value of the porosity of solids by using this relation;
n = e/(1+e)
n = 0.6/(1+0.6)
n = 0.6/1.6
n = 0.375.

And 0.375 is available in the option so it is the correct answer. Option A is answer!
(5)

S.Rajashekar Reddy iiit basar said:   1 decade ago
Dry density of soil is = 1.6g/cc.
Specific gravity of soil = 2.56.
Density of water take it as = 1g/cc.

Then use the relation between dry density and void ratio,

i.e,dry density of soil = (specific gravity*density of water)/(1+void ratio).

Here you got void ratio value then use the relation between porosity and void ratio.

Then you will get answer as 0.375.
(1)

Shubham Narayankar said:   4 years ago
As we take the given value of water density then the answer will come porosity(n) =0.66 by giving confusion of water density the answer will come wrong, for correct answer yo can take water density =1g/cc.

Yd=((G*Yw)/(1+e)),
Yd= 0.6,

n = e / 1+e = 0.375.
(8)

Raval Chaitanya Vajendrakumar said:   9 years ago
The value of water density is given to find the right value of degree of saturation,
As we have found void ratio = 0.6.

We have ,
e * s = w * g,
=> S = (.15 * 2.56)/0.6,
=> S = 64%. Where w = (1.84/1.6)-1.

Aswathy said:   6 years ago
Here,
Dry density, Yd=1.6g/cc.
Specific Gravity, G=2.56.
[Consider, water density, Yw as 1g/cc].
Porosity, n= e/1+e.
Void ratio, e= (GYw/Yd) -1=((2.5*1) /1.6)-1=0.6.
Then, porosity, n= e/1+e=0.6/(1+0.6) =0.375.
(3)

Anonymous said:   9 years ago
If we have to take the density of water as 1 gm/cc then why 1.84 g/cc is given in question?

In order to get the right answer ignore the value given in question.

Munshi said:   8 years ago
Just remember that whatever value of water density is given we have to neglect it, density of water is fixed at 1g/cc.

Ali said:   5 years ago
Dry density = (Gs*water density)/1+e.
Water density = 1 g/cm^3.
1.6 = (2.56*1)/1+e,
e = 0.6,
n = e/1+e,
n = 0.375.
(6)

Kapil said:   7 years ago
Here, e is the void ratio. What is the actual formula to finding out the value of porosity? Please tell me.
(1)

Doyel said:   8 years ago
Taking value of water density as 1.84 g/cc, answer comes to be 0.67.

Is not this the right answer?


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