Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 2 (Q.No. 29)
29.
If the specific gravity of a soil particle of 0.05 cm diameter is 2.67, its terminal velocity while settling in distilled water of viscosity, 0.01 poise, is
Discussion:
12 comments Page 1 of 2.
Davendra Singh said:
5 years ago
(g/18*viscosity )*(G-1) * (d*d).
(9.81/18*0.01) * (2.67-1)* (0.05*0.05),
Answer 0.2275 cm/sec.
(9.81/18*0.01) * (2.67-1)* (0.05*0.05),
Answer 0.2275 cm/sec.
(6)
Trident said:
5 years ago
Agree, @Vasatha Devi G.
Vt =gd^2(dp-dm)/18v.
Vt =gd^2(dp-dm)/18v.
(1)
JEGANATHAN said:
6 years ago
(g/18μ)*(G-1)*(d^2).
(4)
Bhaskarsable said:
7 years ago
Settling velocity = (g/18)(ρs - ρw)(d^2/μ).
= (9.81/18) * (2.67-1) * (((0.05x10^-2)^2)/(0.01x10^-4),
= 0.2275 cm/sec.
= (9.81/18) * (2.67-1) * (((0.05x10^-2)^2)/(0.01x10^-4),
= 0.2275 cm/sec.
Raghav said:
7 years ago
Anyone explain this, please.
(1)
Vasatha devi g said:
8 years ago
To, Calculate Terminal Velocity.
V = Terminal Velocity.
D = Diameter Of a Particle.
g = Acceleration Of Gravity.
v = Viscosity Of Medium.
dp = Density Of Particle.
dm = Density Of Medium.
V = Terminal Velocity.
D = Diameter Of a Particle.
g = Acceleration Of Gravity.
v = Viscosity Of Medium.
dp = Density Of Particle.
dm = Density Of Medium.
(2)
Insan said:
9 years ago
Terminal Velocity = 2(radius of particle)^2 / 9(liq viscosity) x (specific weight of body-sp. wt of liq).
(2)
Yogesh said:
9 years ago
Settling velocity = (g/18)(ρs - ρw)(d^2/μ).
g = 9.81m/s2, ρs = 2.67g/cc, ρw = 1g/cc, d = 0.05cm, μ = 0.01poise.
g = 9.81m/s2, ρs = 2.67g/cc, ρw = 1g/cc, d = 0.05cm, μ = 0.01poise.
(2)
Abhijit said:
9 years ago
Not clear! Please help me.
(2)
Parv said:
9 years ago
Terminal velocity v = (d^2/18*viscosity) * (unit wt of water (G of soil - G of fluid)).
=> (5 * 10^-4) ^ 2/(18 * 10^-4 kn.s/m^2) * (9.81 (2.67 - 1))
= .002275 m/s.
= .2275 cm/s.
=> (5 * 10^-4) ^ 2/(18 * 10^-4 kn.s/m^2) * (9.81 (2.67 - 1))
= .002275 m/s.
= .2275 cm/s.
(1)
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